Twoim problemem jest to, że powszechną NICOŚĆ mylisz z osobistą PUSTKĄ
1.Wzór na wzgl.przewęż.próbki: Z=So-Su/Su *100%, Z-wzgl.przewÄ™.próbki,So-poczÄ…tko.pole przekro.poprzeczne.próbki[mm2],                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                 Su-pole przekr.poprzeczn.prób.po zerwan.[mm2]./// 2.Wzór na granicÄ™ zerwania: Ru=Fu/Su[MPa],Fu-siÅ‚a obciążajÄ…ca w chwili                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                          zerwan.próbki[N], Su-koÅ„cowe pole przekroju poprzecz.prób.po jej zerwan.[mm2]./// 3.Co to dÅ‚ugość wyboczeniowa i od                                                                                                                                                                                                                                                                                                                                                                                                                                                                     czego zależy? - (lw)odpowiada dÅ‚ugoÅ›ci po fali przedstawiajÄ…cej liniÄ™ ugiÄ™cia prÄ™ta przy wybocze.Zależy od sposo.zamocowan.                                                                                                                                                                                                                                                                                                                                                                                                                                                                               obu koÅ„ców prÄ™ta.(rysunki)./// 4.Co to Å›rodek skrÄ™cania ?-to pkt.leżący w pÅ‚aszczyźnie przekroju poprzeczne.taki,że przechodz.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                 przez niego dowoln.siÅ‚a poprzeczna T nie wywoÅ‚a skrÄ™cenia przekroju(samoskrÄ™cen.).W tym pkt.wystÄ™puj.tylko zjawiska Å›cinan.                                                                                                                                                                                                                                                                                                                                                                                                                                                                  i zginania.///5.Jakie zjawiska zachodzÄ… dziÄ™ki tensomet.elektroopo.?-zjawisk.zachodzÄ…ce dziÄ™ki tensom.elektro.to zmiana wymia.                                                                                                                                                                                                                                                                                                                                                                                                                                                                 geometrycznych wraz zezmian.rezystancji./// 6.Napisz wzór na mod.Young'a na podst.ugiÄ™cia belki.; E=3/4 Pel^2/fbh^3[Pa][GPa],                                                                                                                                                                                                                                                                                                                                                                                                                                                                P-siÅ‚a obciążajÄ…ca[kn], f-odlegÅ‚.miÄ™dzy skrajnymi czynnikami[mm], b,h-wym.belki(dÅ‚ugo.,szeroko.)[mm] (rysunek)./// 7.Narysuj                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                     wykres napręż.krytycznych...-(rysunek), σ kr-napręż.krytycz., λgr-smukÅ‚ość graniczna, λ-smukÅ‚o.prÄ™ta,Rm-granica Hooke'a, σH-                                                                                                                                                                                                                                                                                                                                                                                                                                                  naprężenie Hooke'a./// 8.Napisz wzór na sztywność na skrÄ™canie...: G*Is [Nm2], wyznaczamy ze wzoru na kÄ…t skrÄ™cania: φ=Ms*l/                                                                                                                                                                                                                                                                                                                                                                                                                                                             G*Is => GIs= Ms*l/ φ, Is- moment bezwÅ‚adno.na skrÄ™canie[m4]-biegunowy momen.bezwÅ‚adnoÅ›., G-moduÅ‚ Kirchhoffa[Pa], Ms-                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                mom.skrÄ™cajÄ…cy[Nm], φ-kÄ…t skrÄ™cania[-]. ///9. Podaj spos.na wyznacza.mod.Younga: -metod.tensometrycznÄ…, -pomiar ugiÄ™cia belki.                                                                                                                                                                                                                                                                                                                                                                                                                                                                          /// 10.ModuÅ‚ Kirchhoffa-współ.sprężystoÅ›ci. : z prawa Hooke'a: G=Ï„/γ [Pa], γ-kÄ…t odksztaÅ‚c.postaciowe.[-], Ï„-naprężenie Å›cinajÄ…c.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                         [Pa], G-mod.Kirchho.[Pa]. W zależnoÅ›ci od mod.Younga i licz.Poissona: G=E/2(1+Ï‘) [Pa], E-mod.Younga[Pa], Ï‘-liczba Poissona[-].                                                                                                                                                                                                                                                                                                                                                                                                                                                                     ///11.Podstawowe równanie tensometrii oporowej. : R=δL/S, R-rezystan.przewodnik.[om], δ-rezystan.wÅ‚aÅ›ciw.przewodnika[om*                                                                                                                                                                                                                                                                                                                                                                                                                                                                                mm2/m], L-dÅ‚ugość przewodnik.[m], S-pole przekroj.poprzecz.przewodnik.[mm2].///12.Współczynnik Poissona.: Ï‘=-ε'/ ε , Ï‘-wsp.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                 proporcjonal.noszÄ…cy nazwÄ™ liczb.Poissona,speÅ‚niajÄ…cy nierówność., ε'-odksztaÅ‚ce.poprzeczne, ε-odksztaÅ‚.wzdÅ‚użne. ///13.Prawo                                                                                                                                                                                                                                                                                                                                                                                                                                                                           Hooke-a: praw.mechanik.okreÅ›lajÄ…ce zależność odksztaÅ‚cen.od napręże.GÅ‚osi ono,że odksztaÅ‚cen.ciaÅ‚a pod wpÅ‚ywem dziaÅ‚ajÄ…cej na                                                                                                                                                                                                                                                                                                                                                                                                                                                                                    niego siÅ‚y jest wprost proporcjonal.do tej siÅ‚y.Współczynn.miÄ™dzy siÅ‚Ä… a odksztaÅ‚ceniem jest czÄ™sto nazywany współczyn.(moduÅ‚.)                                                                                                                                                                                                                                                                                                                                                                                                                                                        sprężystoÅ›ci. δ=E* ε, E-mod.Younga[Pa], ε-wzglÄ™dne odksztaÅ‚cen.liniowe zgodne z kierunk.obciążenia.///                     Â
                                                                                                                                                                                                                                                                                 14.Wzór na granic.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                     14.Wzór na gran.plastycz.: Re=Fe/So[MPa], Fe-siła obciążająca odpowiadaj.wyraźnej gran.plastyczn.[N], So-początko. pole przek. poprz.                                                                                                                                                                                                                                                                                                                                                                                                                                                            [mm2]./// 15.Siła krytyczna.: Fkr=π^2E Imin/L [N], E-mod.Younga[Pa], Imin-najmniejszy moment bezwładno.przekroj.poprzeczne.                                                                                                                                                                                                                                                                                                                                                                                                                                                             pręt.[m4], L-dł.pręta[m]. Obowiązuje w przypadk.wyboczenia sprężyste.,czyli, gdy naprężen.krytyczn. są mniejsze od granicy sprężys.,                                                                                                                                                                                                                                                                                                                                                                                                                                                                                              lub: Ukr= π^2E/ λ^2, λ-smukłość pręta./// 16.Graficzna interpretacja mod.Younga: Re-gran.plastyczno., Ru-gr.zerwania,Rm-gr.                                                                                                                                                                                                                                                                                                                                                                                                                                                  wytrzymało.,Rsp-gr.sprężystoś.,Rh-gran.prawa Hookea.///
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1.Wzór na wzgl.przewęż.próbki: Z=So-Su/Su *100%, Z-wzgl.przewę.próbki,So-początko.pole przekro.poprzeczne.próbki[mm2],                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                 Su-pole przekr.poprzeczn.prób.po zerwan.[mm2]./// 2.Wzór na granicę zerwania: Ru=Fu/Su[MPa],Fu-siła obciążająca w chwili                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                          ...